<p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';"><font face="굴림"> 협력의 진화를 읽고 세력권 체제에서 가장 안정적이고 인상적인 결과를 보인 루이 나이데거의 알고리즘을 찾아봤는데 중간에 해석이 매끄럽지 않아서 이해가 안 되네요..</font></span></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';"><font face="굴림"> 중간 문단 3줄이 정확하게 해석이 안 되는데 알고리즘 이해를 위해서는 여기가 핵심인 것 같습니다.</font></span></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';"><font face="굴림"> 솔직히 마지막 문단도 제대로 해석한 게 맞는지도 모르겠네요.</font></span></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';"><font face="굴림"><br></font></span></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';"><font face="굴림"> 알고리즘 보면 A1,A2,A3 변수 셋을 쓰는 거 같은데 어디를 어떻게 계산해서 상대방에게 대응한다는 건지..</font></span></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';"><font face="굴림"> 베이스는 범죄자의딜레마이고 둘 다 협력이면 서로 3점을 한 명만 배신일 경우 배신자만 5점 상대는 0점 상호배신인 경우 둘 다 1점을 받는 게임에 참여한 플레이어의 알고리즘입니다.</font></span></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';"><font face="굴림"><br></font></span></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';"><font face="굴림"> 두 번째 문단 해석 좀 부탁드립니다!!</font></span></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';"><font face="굴림"><br></font></span></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';"><font face="굴림"><br></font></span></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';"><font face="굴림"><br></font></span></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">Submitted to Axelrod’s first tournament by Rudy Nydegger.</span></p> <p> </p><p></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">The program begins with tit for tat for the first three moves, except that if it was the only one to cooperate on the first move and the only one to defect on the second move, it defects on the third move.</span></p> <p><span>이 프로그램은 첫 </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">3</span><span>번의 움직임은 팃포탯처럼 시작합니다</span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">, </span><span>첫 번째 협력하고 두 번째와 세 번째 배신하는 유일한 경우를 제외하고</span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">.</span></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">After the third move, its choice is determined from the 3 preceding outcomes in the following manner.</span></p> <p><span>세 번째 움직임 이후</span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">, </span><span>선택은 다음과 같은 방식의 </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">3</span><span>가지 선행 결과로 결정된다</span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">.</span></p> <p> </p><p></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">Let A be the sum formed by counting the other’s defection as 2 points and one’s own as 1 point, and giving weights of 16, 4, and 1 to the preceding three moves in chronological order.</span></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">A</span><span>를 다른 것</span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">(</span><span>다른 알고리즘</span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">)</span><span>의 배신을 </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">2</span><span>점으로 하고 내 알고리즘을 </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">1</span><span>점으로 센 것의 합이라 하면</span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">, ?????????</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">The choice can be described as defecting only when A equals 1, 6, 7, 17, 22, 23, 26, 29, 30, 31, 33, 38, 39, 45, 49, 54, 55, 58, or 61.</span></p> <p> </p><p></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">Thus if all three preceding moves are mutual defection,</span></p> <p><span>따라서</span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">, </span><span>만약 모든 세 번의 앞선 움직임이 상호 배신이라면</span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">,</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">A = 63 and the rule cooperates.</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">A</span><span>는 </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">63</span><span>이고 규칙은 협조이다</span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">.</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">This rule was designed for use in laboratory experiments as a stooge which had a memory and appeared to be trustworthy, potentially cooperative, but not gullible.</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span>이 규칙은 기억을 가졌고</span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">, </span><span>신뢰할 수 있으며</span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">, </span><span>잠재적 협조자이지만 속일 수는 없는 꼭두각시로서 실험실 실험에서 사용하도록 설계되었다</span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">.</span></p> <p> </p><p></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">-> </span><span>알고리즘인가봅니다.. 혹시 해석에 도움이 될지도 몰라서 올려놓습니다.</span></p> <p> </p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">class Nydegger(Player):</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">"""</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">Submitted to Axelrod's first tournament by Rudy Nydegger.</span></p> <p> </p><p></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">The program begins with tit for tat for the first three moves, except </span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">that if it was the only one to cooperate on the first move and the only one to defect on the second move, it defects on the third move. After the third move, its choice is determined from the 3 preceding outcomes in the following manner.</span></p> <p> </p><p></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">Let A be the sum formed by counting the other's defection as 2 points and one's own as 1 point, and giving weights of 16, 4, and 1 to the preceding three moves in chronological order. The choice can be described as defecting only when A equals 1, 6, 7, 17, 22, 23, 26, 29, 30, 31, 33, 38, 39, 45, 49, 54, 55, 58, or 61.</span></p> <p> </p><p></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">Thus if all three preceding moves are mutual defection, A = 63 and the rule cooperates. This rule was designed for use in laboratory experiments as a stooge which had a memory and appeared to be trustworthy, potentially cooperative, but not gullible.</span></p> <p> </p><p></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">Names:</span></p> <p> </p><p></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">- Nydegger: [Axelrod1980]_</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">"""</span></p> <p> </p><p></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">name = "Nydegger"</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">classifier = {</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">'memory_depth': 3,</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">'stochastic': False,</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">'makes_use_of': set(),</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">'long_run_time': False,</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">'inspects_source': False,</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">'manipulates_source': False,</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">'manipulates_state': False</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">}</span></p> <p> </p><p></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">def __init__(self):</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">self.As = [1, 6, 7, 17, 22, 23, 26, 29, 30, 31, 33, 38, 39, 45, 54, 55,</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">58, 61]</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">self.score_map = {(C, C): 0,</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">(C, D): 2,</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">(D, C): 1,</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">(D, D): 3}</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">super(Nydegger, self).__init__()</span></p> <p> </p><p></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">@staticmethod</span></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">[docs] def score_history(my_history, opponent_history, score_map):</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">"""Implements the Nydegger formula A = 16 a_1 + 4 a_2 + a_3"""</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">a = 0</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">for i, weight in [(-1, 16), (-2, 4), (-3, 1)]:</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">plays = (my_history[i], opponent_history[i])</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">a += weight * score_map[plays]</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">return a</span></p> <p> </p><p></p> <p> </p><p></p> <p><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">[docs] def strategy(self, opponent):</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">if len(self.history) == 0:</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">return C</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">if len(self.history) == 1:</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';"># TFT</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">return D if opponent.history[-1] == D else C</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">if len(self.history) == 2:</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">if opponent.history[0: 2] == [D, C]:</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">return D</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">else:</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';"># TFT</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">return D if opponent.history[-1] == D else C</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">A = self.score_history(self.history[-3:], opponent.history[-3:],</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">self.score_map)</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">if A in self.As:</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">return D</span></p> <p><span lang="en-us" style="font-family:'함초롬바탕';"> </span><span lang="en-us" style="letter-spacing:0pt;font-family:'함초롬바탕';">return C</span></p> <p> </p><p></p>
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